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Forum Replies

  1. Rene,
    Hi. Great explanations as always. One quick clarification - in the offset list example towards the end of the network lesson you show applying the offset list to the F0/1 interface. of R2. I assume that you must also apply it to the F0/0 as well (like you did in the example following using distribute-lists)?

    Many thanks,

  2. Hi Rene, there is actually something even deeper to this that you may not have realised. Let’s say the network is stuck in the loop currently, and R2’s best path is via R4 to reach Okay? So since R4 told R2 this is the best path via RIP, this ALSO means that since RIP is distance vector, it means split-horizon would then suppress advertisements of from R2 towards R4. So EVEN IF you change the AD on R4, once the loop is active, lowering the AD of RIP or increasing the AD of OSPF external routes should not affect anything. Since R4’s RI

    ... Continue reading in our forum

  3. Hi Stephen,

    The “core” of this problem is that R2 is learning the route through R4, something that should never happen since it’s a route that went from RIP > OSPF > RIP. We call it a metric redistribution issue since RIP doesn’t have any way to differentiate between an internal or external route…the lower metric from R4 wins. This really is a routing loop which is bad :slight_smile:

    Once R2 installs the route through R4, it will no longer advertise to R4 so the only way for R4 to get to is R3…keep in mind that this is not much of an issue…it

    ... Continue reading in our forum

  4. Hi Rene,

    Please disregard my above post / question. After reviewing it carefully, i noticed it’s all about metric, not AD. It’s my bad!
    Sry for taking your time.


  5. u r the best :+1: well explained i swear to GOD

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