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Forum Replies

  1. Rene,

    A good way to explain this subject that is a little confuse.
    About challenge, I tried to solve it…

    A network 10.0.0.0

    One subnet for 600 hosts -> It’s need a block 1024
    One subnet for 250 hosts. -> It’s need a block 256
    One subnet for 120 hosts. -> It’s need a block 128
    One subnet for 30 hosts. -> It’s need a block 32
    One subnet for 2 hosts. -> It’s need a block 4

    A block of 1024 is like 4x256, which is need 10 hosts bits.

    So…

    Subnet 1: (size 1024)

    network address: 10.0.0.0/22
    netmask: 255.255.252.0
    first host: 10.0.0.1
    last host: 10.0.3.254
    broadcast add

    ... Continue reading in our forum

  2. Hi Rene,

    Can you pls elaborate on how you got this subnet mask? I didn’t get it. thanks
    <>

  3. Hi Lynkaran,

    I’ll explain how to do the first example, see if you can solve them with my technique. Let’s start with 112.10.78.40/22:

    First we need to figure out what the subnet mask since /22 doesn’t tell us much. You need to write this down in binary and convert it to decimal:

    first 8 bits = 11111111 (255 in decimal)
    next 8 bits = 11111111 (255 in decimal)
    next 8 bits = 11111100 (252 in decimal)
    next 8 bits = 00000000 (0 in decimal)

    So now we know the subnet mask is 255.255.252.0

    How many hosts do we have per subnet? There are 2 + 8 host bits so 10 host bits

    ... Continue reading in our forum

  4. Hello Apurva.

    That is exactly correct! Keep in mind as well that the first and last addresses in the range are the network and broadcast addresses respectively so you will have 126 addresses available for hosts.

    I hope this has been helpful!

    Laz

  5. Hi Rene,

    Shouldn’t be for 600 hosts, 3 blocks would suffice? 256*3
    Instead of taking 4 blocks in above solution?

    Rahul

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