We're Sorry, Full Content Access is for Members Only...

If you like to keep on reading, Become a Member Now! Here is Why:

  • Learn any CCNA, CCNP and CCIE R&S Topic. Explained As Simple As Possible.
  • Try for Just $1. The Best Dollar You've Ever Spent on Your Cisco Career!
  • Full Access to our 557 Lessons. More Lessons Added Every Week!
  • Content created by Rene Molenaar (CCIE #41726)

 

315 New Members signed up the last 30 days!

satisfaction-guaranteed

100% Satisfaction Guaranteed!
You may cancel your monthly membership at any time.
No Questions Asked!


Notable Replies

  1. very simple explanation yet so informative. thank you

  2. The best I've seen on this, without straying into

    geeksville and losing me.

  3. Thanks Angel! My goal is to make it as simple as possible :slight_smile:

    The more time you spend at this, the easier it becomes...before you know it you feel like a guru =)

  4. Hi Rene,

    Could you please let me know how many continuous hextet of '0's should be there to be replaced by a ':'.

    Thank you.

  5. Hello Srikanth.

    Whenever you have two or more groups of four 0's, you can replace them with '::' So for example, if you have 2001:0db8:85a3:0000:0000:8a2e:0370:7334 it can be rewritten as 2001:0db8:85a3::8a2e:0370:7334.

    If however you have only one group of four 0's such as in 2001:db8:0000:1:1:1:1:1 it is never replaced with a :: but just with a single 0 like this: 2001:db8:0:1:1:1:1:1.

    Note also that this two-colon replacement may only be applied once in an address, because multiple occurrences would create an ambiguous representation. For example, 2001:0000:0000:0000:1:0000:0000:1 could be rendered as 2001::1:0:0:1 or 2001:0:0:0:1::1 but not as 2001::1::1

    I hope this has been helpful!

    Laz

Continue the discussion forum.networklessons.com

5 more replies

Participants