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Notable Replies

  1. Hi Scott,

    There's no image :slight_smile:


  2. Hello Rene,

    I really appreciate your explanations. they are very intuitive as well a 4 year old could understand, though at times I feel like an infant when trying to wrap my head around some of the terminology.

    Appreciate the help!

    Angel Acosta

  3. Thanks Angel! My goal is to make it as simple as possible :slight_smile:

    The more time you spend at this, the easier it becomes...before you know it you feel like a guru =)

  4. Hi Rene,

    Could you please let me know how many continuous hextet of '0's should be there to be replaced by a ':'.

    Thank you.

  5. Hello Srikanth.

    Whenever you have two or more groups of four 0's, you can replace them with '::' So for example, if you have 2001:0db8:85a3:0000:0000:8a2e:0370:7334 it can be rewritten as 2001:0db8:85a3::8a2e:0370:7334.

    If however you have only one group of four 0's such as in 2001:db8:0000:1:1:1:1:1 it is never replaced with a :: but just with a single 0 like this: 2001:db8:0:1:1:1:1:1.

    Note also that this two-colon replacement may only be applied once in an address, because multiple occurrences would create an ambiguous representation. For example, 2001:0000:0000:0000:1:0000:0000:1 could be rendered as 2001::1:0:0:1 or 2001:0:0:0:1::1 but not as 2001::1::1

    I hope this has been helpful!


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