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Forum Replies

  1. very simple explanation yet so informative. thank you

  2. The best I've seen on this, without straying into

    geeksville and losing me.

  3. Hi Rene,

    Could you please let me know how many continuous hextet of '0's should be there to be replaced by a ':'.

    Thank you.

  4. Hello Srikanth.

    Whenever you have two or more groups of four 0's, you can replace them with '::' So for example, if you have 2001:0db8:85a3:0000:0000:8a2e:0370:7334 it can be rewritten as 2001:0db8:85a3::8a2e:0370:7334.

    If however you have only one group of four 0's such as in 2001:db8:0000:1:1:1:1:1 it is never replaced with a :: but just with a single 0 like this: 2001:db8:0:1:1:1:1:1.

    Note also that this two-colon replacement may only be applied once in an address, because multiple occurrences would create an ambiguous representation. For example, 2001:0000:0000:0000:1:0000:0000:1 could be rendered as 2001::1:0:0:1 or 2001:0:0:0:1::1 but not as 2001::1::1

    I hope this has been helpful!


  5. I approve.

    I actually had a sigh of relief because this made sense and was easy to understand. Felt a bit of pride that I was able to still remember how to do Hex to Dec!!

    IPV6 is a booger but this lesson was helpful with dealing with prefixes!

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